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161 lines
5.2 KiB
Lua
161 lines
5.2 KiB
Lua
--- source https://github.com/daurnimator/luatz/blob/master/luatz/timetable.lua
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-- edited down to just what is needed.
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local Public = {}
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local floor = math.floor
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local strformat = string.format
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local function borrow(tens, units, base)
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local frac = tens % 1
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units = units + frac * base
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tens = tens - frac
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return tens, units
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end
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local function carry(tens, units, base)
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if units >= base then
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tens = tens + floor(units / base)
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units = units % base
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elseif units < 0 then
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tens = tens + floor(units / base)
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units = (base + units) % base
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end
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return tens, units
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end
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local function is_leap(y)
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if (y % 4) ~= 0 then
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return false
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elseif (y % 100) ~= 0 then
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return true
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else
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return (y % 400) == 0
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end
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end
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local mon_lengths = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
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-- Number of days in year until start of month; not corrected for leap years
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local months_to_days_cumulative = {0}
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for i = 2, 12 do
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months_to_days_cumulative[i] = months_to_days_cumulative[i - 1] + mon_lengths[i - 1]
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end
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local function month_length(m, y)
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if m == 2 then
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return is_leap(y) and 29 or 28
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else
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return mon_lengths[m]
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end
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end
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local function day_of_year(day, month, year)
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local yday = months_to_days_cumulative[month]
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if month > 2 and is_leap(year) then
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yday = yday + 1
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end
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return yday + day
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end
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local function leap_years_since(year)
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return floor(year / 4) - floor(year / 100) + floor(year / 400)
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end
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local leap_years_since_1970 = leap_years_since(1970)
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local function normalise(year, month, day, hour, min, sec)
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-- `month` and `day` start from 1, need -1 and +1 so it works modulo
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month, day = month - 1, day - 1
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-- Convert everything (except seconds) to an integer
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-- by propagating fractional components down.
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year, month = borrow(year, month, 12)
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-- Carry from month to year first, so we get month length correct in next line around leap years
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year, month = carry(year, month, 12)
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month, day = borrow(month, day, month_length(floor(month + 1), year))
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day, hour = borrow(day, hour, 24)
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hour, min = borrow(hour, min, 60)
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min, sec = borrow(min, sec, 60)
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-- Propagate out of range values up
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-- e.g. if `min` is 70, `hour` increments by 1 and `min` becomes 10
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-- This has to happen for all columns after borrowing, as lower radixes may be pushed out of range
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min, sec = carry(min, sec, 60) -- TODO: consider leap seconds?
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hour, min = carry(hour, min, 60)
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day, hour = carry(day, hour, 24)
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-- Ensure `day` is not underflowed
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-- Add a whole year of days at a time, this is later resolved by adding months
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-- TODO[OPTIMIZE]: This could be slow if `day` is far out of range
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while day < 0 do
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month = month - 1
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if month < 0 then
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year = year - 1
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month = 11
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end
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day = day + month_length(month + 1, year)
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end
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year, month = carry(year, month, 12)
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-- TODO[OPTIMIZE]: This could potentially be slow if `day` is very large
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while true do
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local i = month_length(month + 1, year)
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if day < i then
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break
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end
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day = day - i
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month = month + 1
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if month >= 12 then
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month = 0
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year = year + 1
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end
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end
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-- Now we can place `day` and `month` back in their normal ranges
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-- e.g. month as 1-12 instead of 0-11
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month, day = month + 1, day + 1
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return {year = year, month = month, day = day, hour = hour, min = min, sec = sec}
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end
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--- Converts unix epoch timestamp into table {year: number, month: number, day: number, hour: number, min: number, sec: number}
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-- @param <number> sec unix epoch timestamp
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-- @return <table> {year: number, month: number, day: number, hour: number, min: number, sec: number}
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function Public.to_timetable(secs)
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return normalise(1970, 1, 1, 0, 0, secs)
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end
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--- Converts timetable into unix epoch timestamp
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-- @param <table> timetable {year: number, month: number, day: number, hour: number, min: number, sec: number}
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-- @return <number>
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function Public.from_timetable(timetable)
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local tt = normalise(timetable.year, timetable.month, timetable.day, timetable.hour, timetable.min, timetable.sec)
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local year, month, day, hour, min, sec = tt.year, tt.month, tt.day, tt.hour, tt.min, tt.sec
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local days_since_epoch =
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day_of_year(day, month, year) + 365 * (year - 1970) + -- Each leap year adds one day
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(leap_years_since(year - 1) - leap_years_since_1970) -
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1
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return days_since_epoch * (60 * 60 * 24) + hour * (60 * 60) + min * 60 + sec
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end
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--- Converts unix epoch timestamp into human readable string.
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-- @param <number> secs unix epoch timestamp
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-- @return <string>
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function Public.to_string(secs)
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local tt = normalise(1970, 1, 1, 0, 0, secs)
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return strformat('%04u-%02u-%02u %02u:%02u:%02d', tt.year, tt.month, tt.day, tt.hour, tt.min, tt.sec)
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end
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--- Converts unix epoch timestamp into a date string.
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-- @param <number> secs unix epoch timestamp
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-- @return <string> With data in format YYYY-MM-DD
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function Public.to_date_string(secs)
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local tt = normalise(1970, 1, 1, 0, 0, secs)
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return strformat('%04u-%02u-%02u', tt.year, tt.month, tt.day)
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end
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return Public
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