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RedMew/utils/timestamp.lua
2018-12-01 16:30:05 +00:00

153 lines
4.9 KiB
Lua

--- source https://github.com/daurnimator/luatz/blob/master/luatz/timetable.lua
-- edited down to just what is needed.
local Public = {}
local floor = math.floor
local strformat = string.format
local function borrow(tens, units, base)
local frac = tens % 1
units = units + frac * base
tens = tens - frac
return tens, units
end
local function carry(tens, units, base)
if units >= base then
tens = tens + floor(units / base)
units = units % base
elseif units < 0 then
tens = tens + floor(units / base)
units = (base + units) % base
end
return tens, units
end
local function is_leap(y)
if (y % 4) ~= 0 then
return false
elseif (y % 100) ~= 0 then
return true
else
return (y % 400) == 0
end
end
local mon_lengths = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
-- Number of days in year until start of month; not corrected for leap years
local months_to_days_cumulative = {0}
for i = 2, 12 do
months_to_days_cumulative[i] = months_to_days_cumulative[i - 1] + mon_lengths[i - 1]
end
local function month_length(m, y)
if m == 2 then
return is_leap(y) and 29 or 28
else
return mon_lengths[m]
end
end
local function day_of_year(day, month, year)
local yday = months_to_days_cumulative[month]
if month > 2 and is_leap(year) then
yday = yday + 1
end
return yday + day
end
local function leap_years_since(year)
return floor(year / 4) - floor(year / 100) + floor(year / 400)
end
local leap_years_since_1970 = leap_years_since(1970)
local function normalise(year, month, day, hour, min, sec)
-- `month` and `day` start from 1, need -1 and +1 so it works modulo
month, day = month - 1, day - 1
-- Convert everything (except seconds) to an integer
-- by propagating fractional components down.
year, month = borrow(year, month, 12)
-- Carry from month to year first, so we get month length correct in next line around leap years
year, month = carry(year, month, 12)
month, day = borrow(month, day, month_length(floor(month + 1), year))
day, hour = borrow(day, hour, 24)
hour, min = borrow(hour, min, 60)
min, sec = borrow(min, sec, 60)
-- Propagate out of range values up
-- e.g. if `min` is 70, `hour` increments by 1 and `min` becomes 10
-- This has to happen for all columns after borrowing, as lower radixes may be pushed out of range
min, sec = carry(min, sec, 60) -- TODO: consider leap seconds?
hour, min = carry(hour, min, 60)
day, hour = carry(day, hour, 24)
-- Ensure `day` is not underflowed
-- Add a whole year of days at a time, this is later resolved by adding months
-- TODO[OPTIMIZE]: This could be slow if `day` is far out of range
while day < 0 do
month = month - 1
if month < 0 then
year = year - 1
month = 11
end
day = day + month_length(month + 1, year)
end
year, month = carry(year, month, 12)
-- TODO[OPTIMIZE]: This could potentially be slow if `day` is very large
while true do
local i = month_length(month + 1, year)
if day < i then
break
end
day = day - i
month = month + 1
if month >= 12 then
month = 0
year = year + 1
end
end
-- Now we can place `day` and `month` back in their normal ranges
-- e.g. month as 1-12 instead of 0-11
month, day = month + 1, day + 1
return {year = year, month = month, day = day, hour = hour, min = min, sec = sec}
end
--- Converts unix epoch timestamp into table {year: number, month: number, day: number, hour: number, min: number, sec: number}
-- @param sec<number> unix epoch timestamp
-- @return {year: number, month: number, day: number, hour: number, min: number, sec: number}
function Public.to_timetable(secs)
return normalise(1970, 1, 1, 0, 0, secs)
end
--- Converts timetable into unix epoch timestamp
-- @param timetable<table> {year: number, month: number, day: number, hour: number, min: number, sec: number}
-- @return number
function Public.from_timetable(timetable)
local tt = normalise(timetable.year, timetable.month, timetable.day, timetable.hour, timetable.min, timetable.sec)
local year, month, day, hour, min, sec = tt.year, tt.month, tt.day, tt.hour, tt.min, tt.sec
local days_since_epoch =
day_of_year(day, month, year) + 365 * (year - 1970) + -- Each leap year adds one day
(leap_years_since(year - 1) - leap_years_since_1970) -
1
return days_since_epoch * (60 * 60 * 24) + hour * (60 * 60) + min * 60 + sec
end
--- Converts unix epoch timestamp into human readable string.
-- @param secs<type> unix epoch timestamp
-- @return string
function Public.to_string(secs)
local tt = normalise(1970, 1, 1, 0, 0, secs)
return strformat('%04u-%02u-%02u %02u:%02u:%02d', tt.year, tt.month, tt.day, tt.hour, tt.min, tt.sec)
end
return Public