## File Upload
- Multipart/form-data file upload
- Multiple form fields and files
Use `req.ParseMultipartForm(16 << 20)` for manually parsing multipart form. It gives
us an option to specify the maximum memory used while parsing the request body.
## Server
`server.go`
```go
package main
import (
"io"
"os"
"net/http"
"github.com/labstack/echo"
mw "github.com/labstack/echo/middleware"
)
func upload(c *echo.Context) error {
req := c.Request()
req.ParseMultipartForm(16 << 20) // Max memory 16 MiB
// Read form fields
name := c.Form("name")
email := c.Form("email")
// Read files
files := req.MultipartForm.File["files"]
for _, f := range files {
// Source file
src, err := f.Open()
if err != nil {
return err
}
defer src.Close()
// Destination file
dst, err := os.Create(f.Filename)
if err != nil {
return err
}
defer dst.Close()
if _, err = io.Copy(dst, src); err != nil {
return err
}
}
return c.String(http.StatusOK, "Thank You! %s <%s>, %d files uploaded successfully.",
name, email, len(files))
}
func main() {
e := echo.New()
e.Use(mw.Logger())
e.Use(mw.Recover())
e.Static("/", "public")
e.Post("/upload", upload)
e.Run(":1323")
}
```
## Client
`index.html`
```html
File Upload
Upload Files
```
## [Source Code](https://github.com/labstack/echo/blob/master/recipes/file-upload)