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fix: auto generate SequenceT for ReaderIOEither

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Signed-off-by: Dr. Carsten Leue <carsten.leue@de.ibm.com>
This commit is contained in:
Dr. Carsten Leue
2023-07-20 16:17:23 +02:00
parent 680c103239
commit 9e32acf551
21 changed files with 5045 additions and 4657 deletions
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27
array/array.go
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@ -15,22 +15,13 @@ func From[A any](data ...A) []A {
}
// MakeBy returns a `Array` of length `n` with element `i` initialized with `f(i)`.
func MakeBy[A any](n int, f func(int) A) []A {
// sanity check
if n <= 0 {
return Empty[A]()
}
// run the generator function across the input
as := make([]A, n)
for i := n - 1; i >= 0; i-- {
as[i] = f(i)
}
return as
func MakeBy[F ~func(int) A, A any](n int, f F) []A {
return G.MakeBy[[]A](n, f)
}
// Replicate creates a `Array` containing a value repeated the specified number of times.
func Replicate[A any](n int, a A) []A {
return MakeBy(n, F.Constant1[int](a))
return G.Replicate[[]A](n, a)
}
func MonadMap[A, B any](as []A, f func(a A) B) []B {
@ -159,21 +150,19 @@ func Of[A any](a A) []A {
}
func MonadChain[A, B any](fa []A, f func(a A) []B) []B {
return array.Reduce(fa, func(bs []B, a A) []B {
return append(bs, f(a)...)
}, Zero[B]())
return G.MonadChain[[]A, []B](fa, f)
}
func Chain[A, B any](f func(a A) []B) func([]A) []B {
return F.Bind2nd(MonadChain[A, B], f)
func Chain[A, B any](f func(A) []B) func([]A) []B {
return G.Chain[[]A, []B](f)
}
func MonadAp[B, A any](fab []func(A) B, fa []A) []B {
return MonadChain(fab, F.Bind1st(MonadMap[A, B], fa))
return G.MonadAp[[]B](fab, fa)
}
func Ap[B, A any](fa []A) func([]func(A) B) []B {
return F.Bind2nd(MonadAp[B, A], fa)
return G.Ap[[]B, []func(A) B](fa)
}
func Match[A, B any](onEmpty func() B, onNonEmpty func([]A) B) func([]A) B {