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Actually protect against deadlock in Dining Philosophers async exercise (#1772)
Swapping forks for one philosopher feels like cheating. It's like one of the philosophers is facing away from the table. Or perhaps it's the only right-handed philosopher at the table. More importantly, there is no effective mechanism to prevent deadlocks. Add that mechanism, it's useful for learning Rust. The new code demonstrates let-else, drop and returning values from a loop. `std::mem::swap` remains in the thread version of the Dining Philosophers exercise for now. This also fixes compilation. `left_fork` and `right_fork` had to be `mut` in `main()` for the workaround to compile.
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@ -41,13 +41,28 @@ impl Philosopher {
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// ANCHOR: Philosopher-eat
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async fn eat(&self) {
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// Pick up forks...
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// Keep trying until we have both forks
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// ANCHOR_END: Philosopher-eat
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let _first_lock = self.left_fork.lock().await;
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// Add a delay before picking the second fork to allow the execution
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// to transfer to another task
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time::sleep(time::Duration::from_millis(1)).await;
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let _second_lock = self.right_fork.lock().await;
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let (_left_fork, _right_fork) = loop {
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// Pick up forks...
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let left_fork = self.left_fork.try_lock();
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let right_fork = self.right_fork.try_lock();
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let Ok(left_fork) = left_fork else {
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// If we didn't get the left fork, drop the right fork if we
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// have it and let other tasks make progress.
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drop(right_fork);
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time::sleep(time::Duration::from_millis(1)).await;
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continue;
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};
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let Ok(right_fork) = right_fork else {
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// If we didn't get the right fork, drop the left fork and let
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// other tasks make progress.
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drop(left_fork);
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time::sleep(time::Duration::from_millis(1)).await;
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continue;
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};
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break (left_fork, right_fork);
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};
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// ANCHOR: Philosopher-eat-body
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println!("{} is eating...", &self.name);
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@ -76,12 +91,6 @@ async fn main() {
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for (i, name) in PHILOSOPHERS.iter().enumerate() {
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let left_fork = Arc::clone(&forks[i]);
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let right_fork = Arc::clone(&forks[(i + 1) % PHILOSOPHERS.len()]);
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// To avoid a deadlock, we have to break the symmetry
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// somewhere. This will swap the forks without deinitializing
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// either of them.
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if i == 0 {
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std::mem::swap(&mut left_fork, &mut right_fork);
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}
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philosophers.push(Philosopher {
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name: name.to_string(),
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left_fork,
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