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Andrew Gallant 656aa12649 printer: fix multi-line replacement bug
This commit fixes a subtle bug in multi-line replacement of line
terminators.

The problem is that even though ripgrep supports multi-line searches, it
is *still* line oriented. It still needs to print line numbers, for
example. For this reason, there are various parts in the printer that
iterate over lines in order to format them into the desired output.

This turns out to be problematic in some cases. #1311 documents one of
those cases (with line numbers enabled to highlight a point later):

    $ printf "hello\nworld\n" | rg -n -U "\n" -r "?"
    1:hello?
    2:world?

But the desired output is this:

    $ printf "hello\nworld\n" | rg -n -U "\n" -r "?"
    1:hello?world?

At first I had thought that the main problem was that the printer was
taking ownership of writing line terminators, even if the input already
had them. But it's more subtle than that. If we fix that issue, we get
output like this instead:

    $ printf "hello\nworld\n" | rg -n -U "\n" -r "?"
    1:hello?2:world?

Notice how '2:' is printed before 'world?'. The reason it works this way
is because matches are reported to the printer in a line oriented way.
That is, the printer gets a block of lines. The searcher guarantees that
all matches that start or end in any of those lines also end or start in
another line in that same block. As a result, the printer uses this
assumption: once it has processed a block of lines, the next match will
begin on a new and distinct line. Thus, things like '2:' are printed.

This is generally all fine and good, but an impedance mismatch arises
when replacements are used. Because now, the replacement can be used to
change the "block of lines" approach. Now, in terms of the output, the
subsequent match might actually continue the current line since the
replacement might get rid of the concept of lines altogether.

We can sometimes work around this. For example:

    $ printf "hello\nworld\n" | rg -U "\n(.)?" -r '?$1'
    hello?world?

Why does this work? It's because the '(.)' after the '\n' causes the
match to overlap between lines. Thus, the searcher guarantees that the
block sent to the printer contains every line.

And there in lay the solution: all we need to do is tweak the multi-line
searcher so that it combines lines with matches that directly adjacent,
instead of requiring at least one byte of overlap. Fixing that solves
the issue above. It does cause some tests to fail:

* The binary3 test in the searcher crate fails because adjacent line
  matches are now one part of block, and that block is scanned for
  binary data. To preserve the essence of the test, we insert a couple
  dummy lines to split up the blocks.
* The JSON CRLF test. It was testing that we didn't output any messages
  with an empty 'submatches' array. That is indeed still the case. The
  difference is that the messages got combined because of the adjacent
  line merging behavior. This is a slight change to the output, but is
  still correct.

Fixes #1311
2021-05-31 21:51:18 -04:00
..
2021-01-17 18:49:51 -05:00

grep-searcher

A high level library for executing fast line oriented searches. This handles things like reporting contextual lines, counting lines, inverting a search, detecting binary data, automatic UTF-16 transcoding and deciding whether or not to use memory maps.

Build status

Dual-licensed under MIT or the UNLICENSE.

Documentation

https://docs.rs/grep-searcher

NOTE: You probably don't want to use this crate directly. Instead, you should prefer the facade defined in the grep crate.

Usage

Add this to your Cargo.toml:

[dependencies]
grep-searcher = "0.1"

and this to your crate root:

extern crate grep_searcher;