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cow1 solution

This commit is contained in:
mo8it
2024-06-29 02:07:56 +02:00
parent a943f5ba32
commit 663a03a17b
3 changed files with 106 additions and 47 deletions

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// Solutions will be available before the stable release. Thank you for testing the beta version 🥰
// This exercise explores the `Cow` (Clone-On-Write) smart pointer. It can
// enclose and provide immutable access to borrowed data and clone the data
// lazily when mutation or ownership is required. The type is designed to work
// with general borrowed data via the `Borrow` trait.
use std::borrow::Cow;
fn abs_all(input: &mut Cow<[i32]>) {
for ind in 0..input.len() {
let value = input[ind];
if value < 0 {
// Clones into a vector if not already owned.
input.to_mut()[ind] = -value;
}
}
}
fn main() {
// You can optionally experiment here.
}
#[cfg(test)]
mod tests {
use super::*;
#[test]
fn reference_mutation() {
// Clone occurs because `input` needs to be mutated.
let vec = vec![-1, 0, 1];
let mut input = Cow::from(&vec);
abs_all(&mut input);
assert!(matches!(input, Cow::Owned(_)));
}
#[test]
fn reference_no_mutation() {
// No clone occurs because `input` doesn't need to be mutated.
let vec = vec![0, 1, 2];
let mut input = Cow::from(&vec);
abs_all(&mut input);
assert!(matches!(input, Cow::Borrowed(_)));
// ^^^^^^^^^^^^^^^^
}
#[test]
fn owned_no_mutation() {
// We can also pass `vec` without `&` so `Cow` owns it directly. In this
// case, no mutation occurs and thus also no clone. But the result is
// still owned because it was never borrowed or mutated.
let vec = vec![0, 1, 2];
let mut input = Cow::from(vec);
abs_all(&mut input);
assert!(matches!(input, Cow::Owned(_)));
// ^^^^^^^^^^^^^
}
#[test]
fn owned_mutation() {
// Of course this is also the case if a mutation does occur. In this
// case, the call to `to_mut()` in the `abs_all` function returns a
// reference to the same data as before.
let vec = vec![-1, 0, 1];
let mut input = Cow::from(vec);
abs_all(&mut input);
assert!(matches!(input, Cow::Owned(_)));
// ^^^^^^^^^^^^^
}
}