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fft: avoid a signed overflow
As a signed integer, 1<<31 overflows, so force it to unsigned. Signed-off-by: Alex Converse <alex.converse@gmail.com>
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9fba8ebe0a
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@ -23,7 +23,7 @@
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#include "libavcodec/dsputil.h"
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#include "fft.h"
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DECLARE_ALIGNED(8, static const int, m1m1)[2] = { 1<<31, 1<<31 };
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DECLARE_ALIGNED(8, static const unsigned int, m1m1)[2] = { 1U<<31, 1U<<31 };
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#ifdef EMULATE_3DNOWEXT
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#define PSWAPD(s,d)\
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@ -70,7 +70,7 @@ void ff_imdct_half_3dn2(FFTContext *s, FFTSample *output, const FFTSample *input
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in1 = input;
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in2 = input + n2 - 1;
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#ifdef EMULATE_3DNOWEXT
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__asm__ volatile("movd %0, %%mm7" ::"r"(1<<31));
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__asm__ volatile("movd %0, %%mm7" ::"r"(1U<<31));
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#endif
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for(k = 0; k < n4; k++) {
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// FIXME a single block is faster, but gcc 2.95 and 3.4.x on 32bit can't compile it
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@ -24,8 +24,8 @@
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#include "fft.h"
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#include "config.h"
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DECLARE_ASM_CONST(16, int, ff_m1m1m1m1)[4] =
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{ 1 << 31, 1 << 31, 1 << 31, 1 << 31 };
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DECLARE_ASM_CONST(16, unsigned int, ff_m1m1m1m1)[4] =
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{ 1U << 31, 1U << 31, 1U << 31, 1U << 31 };
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void ff_fft_dispatch_sse(FFTComplex *z, int nbits);
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void ff_fft_dispatch_interleave_sse(FFTComplex *z, int nbits);
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