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fft: avoid a signed overflow

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As a signed integer, 1<<31 overflows, so force it to unsigned.

Signed-off-by: Alex Converse <alex.converse@gmail.com>
This commit is contained in:
Sean McGovern 2011-09-19 21:32:09 -04:00 committed by Alex Converse
parent 9fba8ebe0a
commit c2d3f56107
2 changed files with 4 additions and 4 deletions
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4
libavcodec/x86/fft_3dn2.c
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@ -23,7 +23,7 @@
#include "libavcodec/dsputil.h" #include "libavcodec/dsputil.h"
#include "fft.h" #include "fft.h"
DECLARE_ALIGNED(8, static const int, m1m1)[2] = { 1<<31, 1<<31 }; DECLARE_ALIGNED(8, static const unsigned int, m1m1)[2] = { 1U<<31, 1U<<31 };
#ifdef EMULATE_3DNOWEXT #ifdef EMULATE_3DNOWEXT
#define PSWAPD(s,d)\ #define PSWAPD(s,d)\
@ -70,7 +70,7 @@ void ff_imdct_half_3dn2(FFTContext *s, FFTSample *output, const FFTSample *input
in1 = input; in1 = input;
in2 = input + n2 - 1; in2 = input + n2 - 1;
#ifdef EMULATE_3DNOWEXT #ifdef EMULATE_3DNOWEXT
__asm__ volatile("movd %0, %%mm7" ::"r"(1<<31)); __asm__ volatile("movd %0, %%mm7" ::"r"(1U<<31));
#endif #endif
for(k = 0; k < n4; k++) { for(k = 0; k < n4; k++) {
// FIXME a single block is faster, but gcc 2.95 and 3.4.x on 32bit can't compile it // FIXME a single block is faster, but gcc 2.95 and 3.4.x on 32bit can't compile it

4
libavcodec/x86/fft_sse.c
View File

@ -24,8 +24,8 @@
#include "fft.h" #include "fft.h"
#include "config.h" #include "config.h"
DECLARE_ASM_CONST(16, int, ff_m1m1m1m1)[4] = DECLARE_ASM_CONST(16, unsigned int, ff_m1m1m1m1)[4] =
{ 1 << 31, 1 << 31, 1 << 31, 1 << 31 }; { 1U << 31, 1U << 31, 1U << 31, 1U << 31 };
void ff_fft_dispatch_sse(FFTComplex *z, int nbits); void ff_fft_dispatch_sse(FFTComplex *z, int nbits);
void ff_fft_dispatch_interleave_sse(FFTComplex *z, int nbits); void ff_fft_dispatch_interleave_sse(FFTComplex *z, int nbits);