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ARM: fix MUL64 inline asm for pre-armv6
Prior to ARMv6, the destination registers of the SMULL instruction must be distinct from the first source register. Marking the output early-clobber ensures it is allocated unique registers. This restriction is dropped in ARMv6 and later, so allowing overlap between input and output registers there might give better code. Signed-off-by: Mans Rullgard <mans@mansr.com>
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@ -41,6 +41,8 @@ static inline av_const int MULL(int a, int b, unsigned shift)
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#define MULH MULH
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#define MULH MULH
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#define MUL64 MUL64
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#if HAVE_ARMV6
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#if HAVE_ARMV6
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static inline av_const int MULH(int a, int b)
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static inline av_const int MULH(int a, int b)
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{
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{
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@ -48,6 +50,13 @@ static inline av_const int MULH(int a, int b)
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__asm__ ("smmul %0, %1, %2" : "=r"(r) : "r"(a), "r"(b));
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__asm__ ("smmul %0, %1, %2" : "=r"(r) : "r"(a), "r"(b));
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return r;
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return r;
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}
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}
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static inline av_const int64_t MUL64(int a, int b)
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{
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int64_t x;
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__asm__ ("smull %Q0, %R0, %1, %2" : "=r"(x) : "r"(a), "r"(b));
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return x;
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}
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#else
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#else
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static inline av_const int MULH(int a, int b)
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static inline av_const int MULH(int a, int b)
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{
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{
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@ -55,15 +64,14 @@ static inline av_const int MULH(int a, int b)
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__asm__ ("smull %0, %1, %2, %3" : "=&r"(lo), "=&r"(hi) : "r"(b), "r"(a));
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__asm__ ("smull %0, %1, %2, %3" : "=&r"(lo), "=&r"(hi) : "r"(b), "r"(a));
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return hi;
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return hi;
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}
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}
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#endif
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static inline av_const int64_t MUL64(int a, int b)
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static inline av_const int64_t MUL64(int a, int b)
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{
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{
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int64_t x;
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int64_t x;
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__asm__ ("smull %Q0, %R0, %1, %2" : "=r"(x) : "r"(a), "r"(b));
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__asm__ ("smull %Q0, %R0, %1, %2" : "=&r"(x) : "r"(a), "r"(b));
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return x;
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return x;
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}
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}
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#define MUL64 MUL64
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#endif
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static inline av_const int64_t MAC64(int64_t d, int a, int b)
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static inline av_const int64_t MAC64(int64_t d, int a, int b)
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{
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{
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