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@ -22,8 +22,8 @@ fn double(n: u64) -> u64 {
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double(UserId(1)); // 🛠️❌
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double(UserId(1)); // 🛠️❌
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```
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```
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The Rust compiler won't implicitly convert to (or from) the underlying type.\
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The Rust compiler won't let you use methods or operators defined on the
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It won't let you use methods or operators defined on the underlying type either:
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underlying type either:
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```rust,compile_fail
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```rust,compile_fail
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# pub struct UserId(u64);
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# pub struct UserId(u64);
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