In CBC mode, when src=dst and we are decrypting a block different
from the first one, we need to save the current block of ciphertext
(which will constitute the initialization vector for the next block)
before we overwrite it.
Signed-off-by: Michael Niedermayer <michaelni@gmx.at>
Basically to make code clearer and adherent to the
standard. RFC 1321, on page 2 states
Let the symbol "+" denote addition of words (i.e., modulo-2^32
addition). Let X <<< s denote the 32-bit value obtained by circularly
shifting (rotating) X left by s bit positions.
on page 3, section 3.3 states:
A four-word buffer (A,B,C,D) is used to compute the message digest.
Here each of A, B, C, D is a 32-bit register.
so the algorithm needs to work with integers that are exactly 32bits
in length. And indeed in struct AVMD5 the MD buffer is declared as
"uint32_t ABCD[4];", while in the function that performs the block
transformation the state variables were "unsigned int"s. On
architectures where sizeof(unsigned int) != sizeof(uint32_t) this
could be a problem, although I can't name such an architecture from
the top of my head.
On a side note, both the reference implementation in RFC 1321 and the
gnulib implementation (used by md5sum program on GNU systems) use
uint32_t in the transform function.
Signed-off-by: Michael Niedermayer <michaelni@gmx.at>
Use log(sqrt(mb->bailout)) instead of log(mb->bailout) because mb->bailout represent
the bailout radius squared, and then simplify the two sqrt().
This is also slightly faster.
Signed-off-by: Michael Niedermayer <michaelni@gmx.at>
Giorgio VazzanaandMichael Niedermayer
